**Solution:** Let a is any integer and a = 6k + 5. We have to show that a is also of the form 3j + 2.

Now, a = 6k + 5

= 3.2k + 3 + 2

= 3(2k + 1) + 2

Let, j = 2k + 1

∴ a = 3j + 2

*Conversely, if, a = 8 = 3.2+2*

And a = 8 = 6.1 + 2

Here 1 and 2 are unique.

So, 8 ≠ 6k + 5.

**Therefore, any integer of the form 6k + 5 is also of the form, but not conversely. ** (Proved)