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# Percentage

## The term “percent” means per hundred. It is a fraction and all time it’s denominator is 100.

* Symbol of percent is expressed as %.

## Some exercise and it’s solution:

Exercise: What is 2 percent of TK 100?
Solution: Let, TK will be x
According to question,
2% of 100 = x

x = 2

TK is 2

Exercise: What number divided by 50 gives 3.6%?

Solution: Let the number will be x.

According to question,

⇒ 1000 x = 50×36

⇒x = 1.8

So the number 1.8.

Exercise: In order to obtain an income of TK 650 from 10% stock at TK 96, one must make an investment of ?

Solution: 10% profit in TK 96 = 96×10%

= 9.6 Tk.

If profit 9.6 Tk. Then investment 96 Tk

”     ”     1     ”       ”         ”   (96÷9.6)”

”     ”     650 ”       ”         ”   (96÷9.6)×650 ”

= 6500 Tk.

Exercise: A man buys Tk. 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. What is the market value of each share market?

Solution: Without 9% dividend the share price is = 20- 20×9%

= 20-1.8

= 18.2

With 12% interest the market value is = 18.2+ 18.2×12%

= 18.2+2.184

= 20.384

21

Exercise: In a country, 60% of the male citizen and 70% of the female citizen are eligible to vote. Seventy percent of the male citizen eligible to vote cast their vote and 60% of the female citizen eligible to vote cast their vote. What fraction of the citizens voted during the election?

Solution: Let, number of male = x

and number of female = y

Exercise: A toy was bought for Tk. 75 and sold at a gain of 8%.What was its selling price in Tk.?

Solution: At 8% gain selling price = 100+8 Tk.

= 108 Tk.

If bought price Tk 100 then selling price = 108 Tk.

”     ”          ”       ”   1   ”       ”         ”   = (108÷100) ”

”     ”         ”       ”     75   ”     ”         ”   = (108÷100)×75 ”

= 81 Tk.

Exercise: If a man’s salary is 20% more than that of his son, how many percent is the son’s salary if compared to the salary of his father?

Solution: Let, man’s salary = m, son’s salary = s

m = s+ s×20%

= s+.20s

= 1.20s

= 83.33%

Exercise: There are 900 students in a school. 4% of them left the school and 50% of the remaining are girls. How many girls remained in the school?

Solution:

In 100 students left the school = 4 students

”   1         ”       ”     ”       ”         ”  = (4÷100) ”

”     900     ”       ”   ”       ”         ”   = (4÷100) ×900”

= 36 studens.

Remaining students = 900-36 = 864 students

Now, In 100 students remained the girls students = 50 students

”     1     ”       ”     ”       ”         ”   = (50÷100) ”

”     864   ”       ”     ”       ”         ”   = (50÷100)×864 ”

=432 students

Exercise: A good has been sold at a loss of 12%. If it could be sold by Tk. 1000 more, there would have been profit of 8%. What is the cost price of that good?

Solution: In 12% loss sell price = (100-12) Tk.

= 88 Tk.

and In 8% profit sell price = (100+8) Tk.

= 108 Tk.

Difference between two sell price = (108 – 88) Tk.

= 20 Tk.

Now, When sell price is 20 Tk. more then cost price =Tk. 100

”        ”       ”     ”   1     ”         ”       ”       ”   = (100÷20) ”

”        ”       ”     ”   1000        ”         ”          = (100÷20)×1000 ”

= 5000 Tk.