Exercise – 10.1-class seven

Read More »## Exercise 10.1|Class seven| Congruence| Part – 2

Problem – 5: In the figure, AD = AE, BD = CE and ∠AEC = ∠ADB. Prove that AB = AC. Particular enunciation: In the figure, AD = AE, BD = CE and ∠AEC = ∠ADB. We have to prove that AB = AC. Proof: In ∆ACE and ∆ADB, AD ...

Read More »## TRIGONOMETRICAL EQUATIONS AND GENERAL VALUES| LECTURE – 1

General expression of all angles, one of whose trigonometrical ratio’s is zero If the sign of an angle be zero, from definition, the length of the perpendicular from any point of one of its arms upon another is zero, so that the two arms must be in the same straight ...

Read More »## Solution exercise 9.1| Class seven| Geometry

Problem-1: In the figure, ∆ABC is a triangle in which ∠ABC = 900, ∠BAC =480 and BD is perpendicular to AC. Find the remaining angles. Solution: Let remaining angles ∠ABD = x, ∠DBC = y and ∠BCD = z. Since BD⊥AC ∴ ∠ADB = ∠CDB = 900 Now, in ∆ABD ...

Read More »## PDF|Trigonometry| Class -10| Part – 3

Click Here: Trigonometery – 3 PDF| Trigonometry| Part – 1 PDF| Trigonometry| Part – 2

Read More »## Exercise 10.1|Class seven| Congruence| Part – 1

Problem – 1: In the figure, CD is the perpendicular bisector of AB, Prove that ∆ADC ≅ ∆BDC. Solution: Particular enunciation: Given that, in the figure, CD is the perpendicular bisector of AB. i.e., AD = BD. We have to prove that, ∆ADC ≅ ∆BDC. Proof: In ∆ADC and ∆BDC, ...

Read More »## If two triangles have the three sides of the one equal to the three sides of the other, each to each, then they are equal in all respects.

If two triangles have the three sides of the one equal to the three sides of the other, each to each, then they are equal in all respects. Particular enunciation: In the ∆ABC and ∆DEF, AB = DE, AC = DF and BC = EF, We have to proved ...

Read More »## If two angles of triangles are equal, then the sides opposite to the equal angles are equal.

If two angles of triangles are equal, then the sides opposite to the equal angles are equal. Particular enunciation: Let ABC be a triangle in which the ∠ACB = the ∠ABC. We have to prove that AB =AC. Proof: If AC and AB are equal, suppose that AB>AC. From BA ...

Read More »## PDF| Calculus| Limit

Calculus| Limit:Calculus – limit

Read More »## Lecture – 4| Abstract Algebra

Problem – 1 : Show that if every element of the group G except the identity element is of order 2, then G is abelian. Solution: Let a, b ∈ G such that a ≠ e, b ≠ e Then a2 = e, b2 = e. Also ab ∈ G ...

Read More »